If it's not what You are looking for type in the equation solver your own equation and let us solve it.
g^2+12g+11=0
a = 1; b = 12; c = +11;
Δ = b2-4ac
Δ = 122-4·1·11
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-10}{2*1}=\frac{-22}{2} =-11 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+10}{2*1}=\frac{-2}{2} =-1 $
| 5n=3124 | | 72=2w+80 | | -5b-9=-4b | | 6(3p+1)-4=9(3p-2)+11 | | 15-19s=-s-15-16s | | 74=2y+34 | | 11+14f=-19+16f | | 4€=w-6€ | | 55=x+70 | | 7x-2=17 | | 6m-7=-m+5+5m | | 123456777788899990-f=1234567890000000000000012345 | | -10p+2=-8p+4 | | (4/x)+(6/(x+8))=8 | | 4x-(9-3x)=-8x-1 | | 9m-3(m+5)=13 | | s-10=8+3s | | 16=8+c | | -10b=-9b+7 | | -20+4r=16 | | 4x+-10=22 | | 14=z/3 | | -1.6r+5=-7.8. | | k-9=5-k | | p+11.3=32.6 | | -2x+12-10x=18 | | -8=6+35x | | -e=3e+8 | | (6n+5)/4=5 | | 3m=4m-(8/5) | | 5(x-3) =35 | | −2/9x+12=−8 |